Through which of the following pairs of point | vedclass

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(C) The equation of the circle is $x^2 + y^2 - 12x + 1 = 0$. To check if a point $(x, y)$ lies on the circle,we substitute the coordinates into the eq

Vedclass · Accepted Answer

$(6, -\sqrt{35}), (3, -\sqrt{26})$

Vedclass · Answer

(C) The equation of the circle is $x^2 + y^2 - 12x + 1 = 0$. To check if a point $(x, y)$ lies on the circle,we substitute the coordinates into the equation and verify if the result is $0$. For the point $(6, -\sqrt{35})$: $6^2 + (-\sqrt{35})^2 - 12(6) + 1 = 36 + 35 - 72 + 1 = 72 - 72 = 0$. So,$(6, -\sqrt{35})$ lies on the circle. For the point $(3, -\sqrt{26})$: $3^2 + (-\sqrt{26})^2 - 12(3) + 1 = 9 + 26 - 36 + 1 = 36 - 36 = 0$. So,$(3, -\sqrt{26})$ lies on the circle. Thus,the circle passes through the pair of points $(6, -\sqrt{35})$ and $(3, -\sqrt{26})$.

Through which of the following pairs of points does the circle $x^2 + y^2 - 12x + 1 = 0$ pass?

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