To estimate $g$ from $g=4 \pi^2 \frac{L}{T^2}$,the error in the measurement of $L$ is $\pm 2 \%$ and the error in the measurement of $T$ is $\pm 3 \%$. The error in the estimated $g$ will be

  • A
    $\pm 8 \%$
  • B
    $\pm 5 \%$
  • C
    $\pm 3 \%$
  • D
    $\pm 6 \%$

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Similar Questions

Two clocks are being tested against a standard clock located in a national laboratory. At $12:00:00$ noon by the standard clock,the readings of the two clocks are
DayClock $1$Clock $2$
Monday$12:00:05$$10:15:06$
Tuesday$12:01:15$$10:14:59$
Wednesday$11:59:08$$10:15:18$
Thursday$12:01:50$$10:15:07$
Friday$11:59:15$$10:14:53$
Saturday$12:01:30$$10:15:24$
Sunday$12:01:19$$10:15:11$

If you are doing an experiment that requires precision time interval measurements,which of the two clocks will you prefer?

The resistance $R = \frac{V}{I}$,where $V = 100 \pm 5 \, \text{volts}$ and $I = 10 \pm 0.2 \, \text{amperes}$. What is the total percentage error in $R$?

The length of a cylinder is measured with a meter rod having a least count of $0.1 \text{ cm}$. Its diameter is measured with vernier calipers having a least count of $0.01 \text{ cm}$. The length of the cylinder is $8.0 \text{ cm}$ and the radius is $4.0 \text{ cm}$. Find the percentage error in the calculated value of the volume. (in $\%$)

Error in the measurement of radius of a sphere is $0.2\%$. The error in the calculated value of its volume is ......... $\%$

If the maximum and minimum temperatures at a place on a day are measured as $44^{\circ} C \pm 0.5^{\circ} C$ and $22^{\circ} C \pm 0.5^{\circ} C$ respectively,then the temperature difference is

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