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(C) The total number of outcomes in the sample space when two dice are thrown is $n(S) = 6 	imes 6 = 36$.Let $E$ be the event of getting numbers whos

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$\frac{2}{9}$

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(C) The total number of outcomes in the sample space when two dice are thrown is $n(S) = 6 	imes 6 = 36$.Let $E$ be the event of getting numbers whose difference is $2$.The favorable outcomes are:$E = \{(1, 3), (2, 4), (3, 5), (4, 6), (3, 1), (4, 2), (5, 3), (6, 4)\}$.Therefore,the number of favorable outcomes is $n(E) = 8$.The probability of the event $E$ is given by $P(E) = \frac{n(E)}{n(S)}$.$P(E) = \frac{8}{36} = \frac{2}{9}$.

Two dice are thrown at the same time. Determine the probability that the difference of the numbers on the two dice is $2$.

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