(B) To verify if $x=2$ is a solution,substitute $x=2$ into the given quadratic equation: $(x-2)(x+3)+1=0$.Substituting $x=2$:$(2-2)(2+3)+1 = (0)(5)+1

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) To verify if $x=2$ is a solution,substitute $x=2$ into the given quadratic equation: $(x-2)(x+3)+1=0$.Substituting $x=2$:$(2-2)(2+3)+1 = (0)(5)+1 = 0+1 = 1$.Since the result is $1$ and not $0$,the left-hand side is not equal to the right-hand side.Therefore,$x=2$ is not a solution of the given quadratic equation.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

Medium

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $(x-2)(x+3)+1=0$; $x=2$.

A
Yes,it is a solution.
B
No,it is not a solution.
C
It is a root of the equation.
D
The equation is not defined at $x=2$.

Explore More

Browse All

Question Bank

All Subjects

Class 10 Questions

Class 10

Mathematics Questions

Chapter

Quadratic Equations

Subtopic

Mix Examples - Quadratic Equations

In quadratic equation $ax^{2} + bx + c = 0$,where $a \neq 0$,$b = 0$,and $D > 0$,then both the roots of the equation are .....

Easy

View Solution

If the discriminant of $x^{2}-10x+(2k-1)=0$ is $40$,then $k=$...............

Easy

View Solution

One of the solutions of the quadratic equation $(x-3)^{2}-4=0$ is ..... .

Medium

View Solution

If the following quadratic equation has two equal and real roots,then find the value of $k$: $k x^{2} - 2 \sqrt{5} x + 4 = 0$.

Medium

View Solution

Solve the following equation using the method of factorization and write its solution set: $4x^{2} + 4x = 15$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $(x-2)(x+3)+1=0$; $x=2$.

Similar Questions

In quadratic equation $ax^{2} + bx + c = 0$,where $a \neq 0$,$b = 0$,and $D > 0$,then both the roots of the equation are .....

If the discriminant of $x^{2}-10x+(2k-1)=0$ is $40$,then $k=$...............

One of the solutions of the quadratic equation $(x-3)^{2}-4=0$ is ..... .

If the following quadratic equation has two equal and real roots,then find the value of $k$: $k x^{2} - 2 \sqrt{5} x + 4 = 0$.

Solve the following equation using the method of factorization and write its solution set: $4x^{2} + 4x = 15$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module