$\int_0^3 (2+x^2) dx = $

  • A
    $\lim _{n \rightarrow \infty} \frac{1}{n} \left[2n + \frac{1^2+2^2+\ldots+(3n)^2}{n^2} \right]$
  • B
    $\lim _{n \rightarrow \infty} \frac{1}{n} \left[3n + \frac{1^2+2^2+\ldots+6n^2}{n^2} \right]$
  • C
    $\lim _{n \rightarrow \infty} \frac{1}{n} \left[6n + \frac{1^2+2^2+\ldots+(3n)^2}{n^2} \right]$
  • D
    $\lim _{n \rightarrow \infty} \frac{1}{n} \left[3n + \frac{1^2+2^2+\ldots+3n^2}{n^2} \right]$

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$\lim _{n \rightarrow \infty} \frac{1}{n} \sum_{j=1}^{n} \frac{(2 j-1)+8 n}{(2 j-1)+4 n}$ का मान ज्ञात कीजिए।

$\lim _{n}$ ${\rightarrow \infty}\left[\left(1+\frac{1}{n^2}\right)\left(1+\frac{2^2}{n^2}\right) \ldots \left(1+\frac{n^2}{n^2}\right)\right]^{1 / n}=$

यदि $\lim _{n \rightarrow \infty} \frac{1}{n} \log \left(\frac{(2 n)!}{n^n \cdot n!}\right)=\int_1^2 f(x) d x$ है, तो $f(x)=$

यदि $k \in N$ है,तो $\lim _{n \rightarrow \infty}\left[\frac{1}{n+1}+\frac{1}{n+2}+\frac{1}{n+3}+\ldots+\frac{1}{k n}\right]=$

$\lim _{n \rightarrow \infty}\left[\frac{\sqrt{n^2-1^2}}{n^2}+\frac{\sqrt{n^2-2^2}}{n^2}+\frac{\sqrt{n^2-3^2}}{n^2}+\ldots+\frac{\sqrt{n^2-n^2}}{n^2}\right]=$

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