A metal ball immersed in alcohol weighs W_1 a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The apparent weight of a body immersed in a liquid is given by $W_{app} = W_{real} - F_B$,where $F_B$ is the buoyant force.$F_B = V_{submerged} \c

Vedclass · Accepted Answer

$W_1 < W_2$

Vedclass · Answer

(C) The apparent weight of a body immersed in a liquid is given by $W_{app} = W_{real} - F_B$,where $F_B$ is the buoyant force.$F_B = V_{submerged} \cdot \rho_{liquid} \cdot g$.Since the coefficient of cubical expansion of the metal is less than that of alcohol,we can assume the volume $V$ of the metal ball remains approximately constant as temperature increases.At $0^{\circ}C$,$W_1 = W_0 - V \rho_0 g$,where $\rho_0$ is the density of alcohol at $0^{\circ}C$.At $59^{\circ}C$,$W_2 = W_0 - V \rho_{59} g$,where $\rho_{59}$ is the density of alcohol at $59^{\circ}C$.As temperature increases,the density of alcohol decreases,so $\rho_{59} Since $\rho_{59} Therefore,$W_0 - V \rho_{59} g > W_0 - V \rho_0 g$,which implies $W_2 > W_1$ or $W_1 < W_2$.

$A$ metal ball immersed in alcohol weighs $W_1$ at $0^{\circ}C$ and $W_2$ at $59^{\circ}C$. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol,it can be shown that

Similar Questions

One quality of a thermometer is that its heat capacity should be small. If $P$ is a mercury thermometer,$Q$ is a resistance thermometer,and $R$ is a thermocouple type,then:

$A$ block of ice at $0^{\circ}C$ falls from a height of $1 \ km$ onto an insulating surface. If all its kinetic energy is converted into heat,what fraction of the ice will melt? (Take $g = 10 \ m/s^{2}$ and latent heat of fusion of ice $L = 3.36 \times 10^{5} \ J/kg$)

$A$ lead bullet moving with velocity '$v$' strikes a wall and stops. If $50\%$ of its energy is converted into heat,then the increase in temperature is ($s =$ specific heat of lead,$J =$ mechanical equivalent of heat).

What is the main difference between the $P-T$ phase diagram of water and $CO_2$?

$A$ hailstone of mass $42 \,g$ falls from a height of $1.8 \,km$. If its entire potential energy is converted into latent heat, what is the mass of the hailstone remaining when it reaches the ground (in $\,g$)? $\left(g=10 \,ms^{-2}, L_{\text{ice}}=3.36 \times 10^5 \,J \,kg^{-1}\right)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module