Arrange the following carbocations in increas | vedclass

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Question

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the positively charged carbon atom.$(I)$ $CH

Vedclass · Accepted Answer

$IV < II < III < I$

Vedclass · Answer

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the positively charged carbon atom.$(I)$ $CH_3O-C_6H_4-CH_2^+$: The $-OCH_3$ group exerts a strong $+M$ (mesomeric) effect,which significantly stabilizes the carbocation.$(II)$ $C_6H_5-CH_2^+$: This is a benzyl carbocation,stabilized by resonance with the benzene ring.$(III)$ $CH_3-C_6H_4-CH_2^+$: The $-CH_3$ group exerts a $+I$ (inductive) effect and hyperconjugation,providing moderate stabilization.$(IV)$ $CH_3-CH_2-CH_2^+$: This is a primary alkyl carbocation,which is the least stable among the given options.Comparing these,the order of stability is: $IV < II < III < I$.

Arrange the following carbocations in increasing order of stability:

Similar Questions

Write structures of various carbocations that can be obtained from $2-$methylbutane. Arrange these carbocations in order of increasing stability.

Which of the following carbocations is the most stable?

Arrange the following free radicals in the correct order of their stability:
$(i)$ $CH_2=\dot{C}H$
$(ii)$ $\dot{C}H_3$
$(iii)$ $CH_3-\dot{C}H-CH_3$
$(iv)$ $(CH_3)_3\dot{C}$

Arrange the carbanions,$(CH_3)_3\overline{C}$,$\overline{C}Cl_3$,$(CH_3)_2\overline{C}H$,$C_6H_5\overline{C}H_2$ in order of their decreasing stability:

Which of the following is more stable than the remaining three?

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