$\mathop {\lim }\limits_{x \to 1} f(x)$ ज्ञात कीजिए,जहाँ $f(x) = \begin{cases} x^{2}-1, & x \leq 1 \\ -x-1, & x > 1 \end{cases}$

  • A
    $0$
  • B
    $-2$
  • C
    $1$
  • D
    अस्तित्व में नहीं है

Explore More

Similar Questions

यदि $\lim_{x \rightarrow 0} [1 + x \ln(1 + b^2)]^{\frac{1}{x}} = 2b \sin^2 \theta$,जहाँ $b > 0$ और $\theta \in (-\pi, \pi]$ है,तो $\theta$ का मान ज्ञात कीजिए।

$\mathop {\lim }\limits_{x \to \infty } \frac{{{x^2}\sin \frac{1}{x} - x}}{{1 - |x|}}$ का मान है

Difficult
View Solution

यदि $\Delta(x) = \begin{vmatrix} e^x & -1 \\ \sin x - 1 & 1 \end{vmatrix}$ है,तो $\lim_{x \rightarrow 0} \frac{\Delta(x)}{x} = $

$\mathop {\lim }\limits_{x \to {0^ + }} {\left( {\sec \sqrt x } \right)^{\frac{{10}}{x}}}$ का मान ज्ञात कीजिए।

मान लीजिए कि सभी प्राकृतिक संख्याओं $n$ के लिए $x_n = (2^n + 3^n)^{\frac{1}{2n}}$ है। तो,

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo