જો $\alpha > \beta > 0$ એ સમીકરણ $ax^2 + bx + 1 = 0$ ના બીજ હોય,અને $\lim_{x}$ ${\rightarrow \frac{1}{\alpha}} \left( \frac{1 - \cos(x^2 + bx + a)}{2(1 - \alpha x)^2} \right)^{\frac{1}{2}} = \frac{1}{k} \left( \frac{1}{\beta} - \frac{1}{\alpha} \right)$ હોય,તો $k$ ની કિંમત શોધો.

  • A
    $2\beta$
  • B
    $2\alpha$
  • C
    $\alpha$
  • D
    $\beta$

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જો $\lim _{x \rightarrow 0} \frac{[(a-n) n x-\tan x] \sin n x}{x^2}=0, (n \neq 0)$ હોય,તો $a$ ની ન્યૂનતમ શક્ય ધન કિંમત શોધો.

જો $\mathop {\lim }\limits_{x \to 1} \frac{{{x^2} - ax + b}}{{x - 1}} = 3$ હોય,તો $a + b$ ની કિંમત શોધો.

જો $\lim_{x \to 3} \frac{x^2 - ax - 3b}{x - 3} = 5$ હોય, તો $a + b =$ શોધો.

ધારો કે $\alpha(a)$ અને $\beta(a)$ એ સમીકરણ $(\sqrt[3]{1+a}-1) x^2+(\sqrt{1+a}-1) x+(\sqrt[6]{1+a}-1)=0$ ના બીજ છે,જ્યાં $a > -1$. તો $\lim _{a \rightarrow 0^{+}} \alpha(a)$ અને $\lim _{a \rightarrow 0^{+}} \beta(a)$ શું થાય?

જો $\mathop {\lim }\limits_{x \to \infty } \left[ {\frac{{{x^3} + 1}}{{{x^2} + 1}} - (ax + b)} \right] = 2$ હોય,તો

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