यदि $a, b$ और $c$ तीन भिन्न वास्तविक संख्याएँ हैं और $\lim _{x \rightarrow \infty} \frac{(b-c) x^2+(c-a) x+(a-b)}{(a-b) x^2+(b-c) x+(c-a)}=\frac{1}{2}$,तो $a+2 c=$

  • A
    $b$
  • B
    $2 b$
  • C
    $3 b$
  • D
    $4 b$

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