यदि $\frac{x^3+3}{(x-3)^3}=a+\frac{b}{x-3}+\frac{c}{(x-3)^2}+\frac{d}{(x-3)^3}$ है, तो $(a+d)-(b+c)=$

  • A
    $49$
  • B
    $15$
  • C
    $-30$
  • D
    $-5$

Explore More

Similar Questions

$\begin{aligned} & \text{यदि } \frac{4x^2+5x^4+7}{(x^2+1)(x^4+x^2+1)} = \frac{Ax+B}{x^2+1} \\ & + \frac{Cx^3+Dx^2+Ex+F}{x^4+x^2+1}, \text{ तो } \\ & B+2(D+F+E)-C \cdot A = \end{aligned}$

यदि $\frac{d}{d x}\left(\frac{2 x+1}{(x+1)^2(x-2)}\right)=\frac{A}{(x-2)^2}+\frac{B}{(x+1)^3}+\frac{C}{(x+1)^2}$ है, तो $A+B+C=$

यदि $\frac{4 x^3+16 x+7}{\left(x^2+4\right)^2}=\frac{A x+B}{x^2+4}+\frac{C x+D}{\left(x^2+4\right)^2}$ है,तो $A, B, C, D$ में शून्येतर (non-zero) मानों की संख्या क्या है?

यदि $\frac{x^2-x+1}{(x^2+1)(x^2+x+1)}=\frac{Ax+B}{x^2+1}+\frac{Cx+D}{x^2+x+1}$ है, तो $A+2B+C+2D=$

यदि $\frac{-x^2+6x+1}{(x-1)^2(x^2+2)} = \frac{A}{x-1} + \frac{B}{(x-1)^2} + \frac{Cx-3}{x^2+2}$ है,तो $A+B+C=$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo