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(B) Let the total number of families be $x$.Let $A$ be the set of families that own cell phones,so $n(A) = \frac{65}{100}x$.Let $B$ be the set of fami

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$30000$

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(B) Let the total number of families be $x$.Let $A$ be the set of families that own cell phones,so $n(A) = \frac{65}{100}x$.Let $B$ be the set of families that own scooters,so $n(B) = 15000$.The number of families that own both is $n(A \cap B) = \frac{15}{100}x$.Since every family owns at least one,$n(A \cup B) = x$.Using the formula $n(A \cup B) = n(A) + n(B) - n(A \cap B)$,we have:$x = \frac{65x}{100} + 15000 - \frac{15x}{100}$$x = \frac{50x}{100} + 15000$$x = 0.5x + 15000$$0.5x = 15000$$x = \frac{15000}{0.5} = 30000$.Thus,the total number of families in the town is $30000$.

In a certain town,$65\%$ of families own cell phones,$15000$ families own scooters,and $15\%$ of families own both. Given that every family owns at least one of the two,the total number of families in the town is:

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