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(C) The height of the liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{rdg}$,where $T$ is the surface tension,$	h

Vedclass · Accepted Answer

Minimum when water temperature is $4^{\circ}C$

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(C) The height of the liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{rdg}$,where $T$ is the surface tension,$	heta$ is the angle of contact,$r$ is the radius of the tube,$d$ is the density of the liquid,and $g$ is the acceleration due to gravity.For water,the density $d$ is maximum at $4^{\circ}C$.Since the height $h$ is inversely proportional to the density $d$ $(h \propto \frac{1}{d})$,the height $h$ will be minimum when the density $d$ is maximum.Therefore,the height up to which water will rise in a capillary tube is minimum at $4^{\circ}C$.

The height up to which water will rise in a capillary tube will be

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Two capillary tubes of same diameter are kept vertically in two liquids whose densities are in the ratio $4:3$. If their surface tensions are in the ratio $6:5$,the ratio of heights $\left(\frac{h_1}{h_2}\right)$ of liquids in the two capillary tubes is (Their angle of contacts are same).

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