The phase difference between input and output voltages of a $CE$ (common emitter) amplifier circuit is........$^o$.

In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$, then the power gain in the circuit is:

Three amplifiers,each having a voltage gain of $10$,are connected in series. The resultant gain would be

$A$ transistor is operated in common emitter configuration at $V_C = 2 \, V$ such that a change in the base current from $100 \, \mu A$ to $300 \, \mu A$ produces a change in the collector current from $10 \, mA$ to $20 \, mA$. The current gain is

If $\alpha = 0.98$ and the current through the emitter $i_e = 20 \, mA$,the value of $\beta$ is