In Delta ABC,AB = 9 , text{cm} and BC = 12 , | vedclass

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(D) Let the third side of the triangle be $AC = b$.According to the triangle inequality theorem,the sum of any two sides of a triangle is greater than

Vedclass · Accepted Answer

$x = 24, y = 42$

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(D) Let the third side of the triangle be $AC = b$.According to the triangle inequality theorem,the sum of any two sides of a triangle is greater than the third side,and the difference of any two sides is less than the third side.$1$. $AB + BC > AC \implies 9 + 12 > b \implies b $2$. $BC - AB 3$.So,$3 The perimeter $P = AB + BC + AC = 9 + 12 + b = 21 + b$.Since $3 $3 + 21 $24 Comparing this with $x < P < y$,we get $x = 24$ and $y = 42$.

In $\Delta ABC$,$AB = 9 \, \text{cm}$ and $BC = 12 \, \text{cm}$. If $x < \text{perimeter of } \Delta ABC < y$,then find the values of $x$ and $y$.

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