sin^{-1}left(frac{2sqrt{2}}{3}right) + sin^{- | vedclass

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(B) ધારો કે $\alpha = \sin^{-1}\left(\frac{2\sqrt{2}}{3}\right)$. તેથી $\sin \alpha = \frac{2\sqrt{2}}{3}$.$\cos^2 \alpha = 1 - \sin^2 \alpha = 1 - \f

Vedclass · Accepted Answer

$\frac{\pi}{2}$

Vedclass · Answer

(B) ધારો કે $\alpha = \sin^{-1}\left(\frac{2\sqrt{2}}{3}\right)$. તેથી $\sin \alpha = \frac{2\sqrt{2}}{3}$.$\cos^2 \alpha = 1 - \sin^2 \alpha = 1 - \frac{8}{9} = \frac{1}{9}$ હોવાથી,$\cos \alpha = \frac{1}{3}$ મળે.આમ,$\alpha = \cos^{-1}\left(\frac{1}{3}\right)$.આ કિંમત પદાવલિમાં મૂકતા,આપણને $\cos^{-1}\left(\frac{1}{3}\right) + \sin^{-1}\left(\frac{1}{3}\right)$ મળે.નિત્યસમ $\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}$ નો ઉપયોગ કરતા,જવાબ $\frac{\pi}{2}$ મળે છે.

$\sin^{-1}\left(\frac{2\sqrt{2}}{3}\right) + \sin^{-1}\left(\frac{1}{3}\right)$ નું મૂલ્ય કેટલું થાય?

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