यदि $\sum_{r=1}^{30} \frac{r^2({}^{30}C_r)^2}{{}^{30}C_{r-1}} = \alpha \times 2^{29}$ है,तो $\alpha$ का मान ज्ञात कीजिए।

  • A
    $126$
  • B
    $626$
  • C
    $357$
  • D
    $465$

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यदि $a$ और $d$ दो सम्मिश्र संख्याएँ हैं,तो निम्नलिखित श्रेणी के $(n + 1)$ पदों का योग $a{C_0} - (a + d){C_1} + (a + 2d){C_2} - \dots$ क्या होगा?

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योगफल $\sum\limits_{i = 0}^m {\binom{10}{i}} {\binom{20}{m - i}}$,(जहाँ $\binom{p}{q} = 0$ यदि $p < q$),तब अधिकतम होता है जब $m$ है

मान लीजिए $S_1 = \sum_{j=1}^{10} j(j-1) \binom{10}{j}$,$S_2 = \sum_{j=1}^{10} j \binom{10}{j}$,और $S_3 = \sum_{j=1}^{10} j^2 \binom{10}{j}$.
कथन $(A) : S_3 = 55 \times 2^9$
कारण $(R) : S_1 = 90 \times 2^8$ और $S_2 = 10 \times 2^8$

यदि $^nC_r = C_r$ और $2 \frac{C_1}{C_0} + 4 \frac{C_2}{C_1} + 6 \frac{C_3}{C_2} + \dots + 2n \frac{C_n}{C_{n-1}} = 650$ है,तो $^nC_2 =$

यदि $\binom{10}{2} + \binom{10}{3} + \binom{11}{4} + \binom{12}{5} + \binom{13}{6} = \binom{14}{r}$ है,तो $r = \dots$

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